$$W = 10 \cdot 5 = 50 J$$
$$W = \Delta KE$$
$$v^2 = u^2 + 2as$$
$$W = F \cdot s$$
A force of 10 N is applied to an object, causing it to move 5 m in the direction of the force. Calculate the work done. dc pandey physics class 11 pdf download part 1 work
where $v = 0$ (final velocity), $u = 4$ m/s (initial velocity), $a = -\frac{5}{2}$ m/s$^2$ (acceleration), and $s$ is the displacement.
$$s = \frac{u^2}{2a} = \frac{4^2}{2 \cdot \frac{5}{2}} = \frac{16}{5} m$$ $$W = 10 \cdot 5 = 50 J$$
Now, we can calculate the work done:
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